a) Ta có: \(BCNN(10, 15) = 30\), nên:
\(\dfrac{7}{10} = \dfrac{7 \times 3}{10 \times 3} = \dfrac{21}{30}\)
\(\dfrac{11}{15} = \dfrac{11 \times 2}{15 \times 2} = \dfrac{22}{30}\)
Vì \(21 < 22\) nên \(\dfrac{21}{30} < \dfrac{22}{30}\), do đó \(\dfrac{7}{10} < \dfrac{11}{15}\).
b) Ta có: \(BCNN(8, 24) = 24\), nên:
\(\dfrac{-1}{8} = \dfrac{-1 \times 3}{8 \times 3} = \dfrac{-3}{24}\)
Vì \(-3 > -5\) nên \(\dfrac{-3}{24} > \dfrac{-5}{24}\), do đó \(\dfrac{-1}{8} > \dfrac{-5}{24}\).